C program discussion how 2 came before 97

Question

Plzz asap
https://code.sololearn.com/cOh5hTPL1EJ7/?ref=app

Answer 1

1. foo() is executed, hence 2 is printed (line 6)
2. The printf prints i which is 97.

So the output is 297

Answer 2

Line 6: foo(&i); // prints 2

Line 8: printf("%d", *p); // prints 97

Output:
297

Answer 3

Because you invoke foo() at line 6. Number 2 was printed inside foo() at line 19.

Number 97 was printed inside main() at line 8

You need to have a forward declaration of foo(), modern C compiler considers a invocation of foo to be inappropriate because foo() is defined after main() wherei foo() was invoked.

Add this line in main at line 5 before foo is invoked at line 6

void foo( int* );

Answer 4

Brother I want to know how 2 is printed before 97 because the value print function is before is 97