Array operations in c++

Question

how can we double each element inside an array in c++. We must have 2 arrays, the first must contain the letters to be doubled and the second will be an empty array which will receive each letter of the first array twice --> a becomes aa, b becomes bb etc...

I'm new to c++ so operations with array I don't know.

Here is the code where I doubled each elements without array

https://code.sololearn.com/cI5ofFsTwGyQ/?ref=app

Answer 1

Take first array as character array like :
char a[] = "abcd";
2nd take it as string array string aa[]={};
Then add aa[i]+=a[i]+a[i]; then print array.
hope it helps.....

edit:
need character to convert to string first this way..

Answer 2

Jayakrishna🇮🇳 I tried then I got an error --> https://code.sololearn.com/cX1dS0K5AQej/?ref=app

Answer 3

#include <iostream>
using namespace std;

int main() {
char a[] = "abc";

string aa[3] = {}; //array size needed

for (int i=0; i < 3; i++){
aa[i] += a[i];
aa[i] += a[i]; //two times add

cout << aa[i] << endl;
}

return 0;
}

edit:
Noël Julmiste Fils
//you can do this by string array also and here is having single array :

#include <iostream>
using namespace std;

int main() {
string a[] = {"a","b","c"};

for (int i=0; i < 3; i++){
a[i] = a[i]+a[i];

cout << a[i] << endl;
}
return 0;
}