Easier way to do this? #SOLVED

Question

CODE LINK:
https://code.sololearn.com/cy8bO00Z8a64

I need to check all combinations of rock paper scissors game. I can do this with 9 if`s, but can i do it easier?

if img == rock and img2 == rock:
res.set("Tie!")
if img == rock and img2 == paper:
res.set('Computer won!')
if img == rock and img2 == scissors:
res.set('You won!')

Answer 1

Hello Artur

I would use a dictionary. Keys = Rock, Paper and Scissor.
Values = looses against key.
https://code.sololearn.com/c69g4Y8klwfZ/?ref=app

Answer 2

I'm sure this could be done with some type of lambda, map thingy where you have lists inside of lists where it returns false or true depending on the case.

Answer 3

Thank you, its actually pretty smart and simple!

Answer 4

Artur
Your welcome!

Answer 5

Can I please see your entire code?

Answer 6

Denise, i have a question about line wins[you]==comp. Wins[you] is same as Wins["Rock"] so it returns scissors?

Answer 7

Artur

Yes.
dictonary[key] = value
So wins["Rock"] returns "Scissor", wins["Scissor"] returns "Paper" and wins["Paper"] returns "Rock"

Answer 8

Whenever I run this code Artur it output is You Win!

Answer 9

Ashwin Kumar gavet you changed the key? In this example 'you' is always rock, so output is same every time

Answer 10

Ava Alford, you can see the whole code now, i included it to post. But you need to use tkinter and have 5 images in order to make it work