how to change this into an array

Question

#include <iostream>
using namespace std;

int main() {
int n;
cin>>n;
int nums=0;
cin>>nums;
int min = nums;
for(int i=1; i<n; i++) {cin>>nums;
if(nums<min)
min = nums;
}
cout << min;

return 0;
}

Answer 1

Instead of int variable nums, declare an array like int nums[n] then use like nums[i] in loop.
Comment //cin>>nums;

before trying, revise lesson arrays;

Answer 2

https://code.sololearn.com/c8zh18xM5LQ6/?ref=app

Answer 3

Jayakrishna🇮🇳 i got it right but i am unsatisfied xD i want to make the array instead of [5] it can accompany any size []

Answer 4

You can do like this:

int n ;
cin >> n;
int ages[n];
But it is not recommended. Array are fixed length. You should mention length at compile time and you can't change it's size during run time.

If you need, then use a vector type. It's a dynamic in nature. You can say it is like a dynamic array.

Answer 5

thanks alot Jayakrishna🇮🇳

Answer 6

Jayakrishna🇮🇳 i still couldnt fix it into an array. 😭

Answer 7

Post your try!!

Answer 8

didnt save Jayakrishna🇮🇳 :) i will try again xD

Answer 9

Save it and share link..