is the following allowed in C ? ( root over a^2 + b^2 )

Question

printf("Sum : %d", pow((pow(entity1, 2) + pow(entity2, 2)), 1 / 2));

everytime i run this, it prints Sum : 0

Answer 1

1/2 result 0 in c.
So pow(n, 0) is 1.0000 a double value..
If you are trying squire root then use sqrt() function..

what are entity1, entity2 values?
it should result always 1, not 0
pow() returns a double type value and converting %d truncates precision, or garbage value..

edit:
hmmm
printf("Sum : %lf", sqrt(pow(entity1, 2) + pow(entity2, 2)));

Hope it helps..

Answer 2

Or you can write pow(n, 1.0/2) or pow(n, 0.5)

Answer 3

If you are getting 0, then something else is terribly wrong in the program. I cannot say what it is without seeing the rest of the program. At least part of the problem is that the format specifier is incorrect. It should be %f, not %d. Another problem was mentioned already, regarding integer math versus floating point math.

There is a better function than either pow or sqrt that performs the exact calculation you want. It is the hypot function.

printf("Sum : %f", hypot(entity1, entity2));

Answer 4

Jayakrishna🇮🇳 Brian YUGRAJ

thank you guys...i understood the things.

i know now why i was getting zero, and ty for letting me know about the new functions.... the hypotenuse is easier to use.