c++

Question

Write a program that can be used to express a fraction in its lowest form.
Functions

In order to complete this task, you are expected to complete the implementation of the three
functions described below.

 void displayFraction(int a, int b)
Takes two integer numbers and display them in a fraction format such as a/b. Use default
values for the parameters of this function so that if the function is called without
parameters 0/1 is displayed and when called with one parameter (say x), then x/1 is
displayed. Note that this function should simply display what it is given even if it is
invalid.

 int gcd(int a, int b)
Takes two positive integers and returns the greatest common divisor of the two numbers.
The greatest common divisor of any two numbers a and b is the largest positive
integer c that is a divisor of both a and b. The number c is a divisor of b if the remainder
after dividing b by c is zero. When passing 0 or a negative value as any one of these
parameters, the function should return -1.

 bool reduceFraction(int &num, int &denom)
Takes two integers representing the numerator and denominator of a fraction. Reduces
the fraction to its lowest form. For example, the result of reducing 20
4 is 5
1 . When
passing 0 or a negative value as any one of these parameters, the function should
return false, otherwise it should return true.

Main program
Write a program called References.cpp that uses the above functions. The program should
prompt the user for a numerator and denominator. When given valid input, it should display
the GCD of the two input values and then display the given fraction, the fraction in its
lowest form as well as the fraction in decimal format.

The following is a sample test run (user input is shown in bold):
Fraction Reduction
-------------------------------
Enter the numerator: 4
Enter the denominator: 20
The GCD of 4 and 20 is 4
The lowest form of 4/20 is 1/5 = 0.2

Answer 1

Is this your homework? Ppl will more likely help you if you show them what you have done so far and tell them what exactly your problem is.

Answer 2

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Answer 3

OH MY 😲 look at all these words, I'm not reading that 😂

Answer 4

#include <iostream>
using namespace std;

int main() {
int b,n;
cin>>b;
cin>>n;
for(int i=b;i>1;i--)
{
if(b%i!=0 || n%i!=0)
{}
else
{
b=b/i;
n=n/i;
}
}
cout<<b<<"/"<<n<<endl;
return 0;
}