why is the output of "y" 55?

Question

static void Main(string[] args)
{
string[] num = new string[3]{"54230","677809","90132"};
for(int i=0;i<3;i++){
string a = num[1];
int y= Convert.ToInt32(a[2]);
Console.WriteLine(a[2]);
Console.WriteLine(y);}
}

Answer 1

Andrey

a[2] = 7

When you convert "7" to integer then you get ASCII value which is 55

Answer 2

Andrey

1 - as a[2] gives "7" which is consider as a character so to get 7 as an integer you have to make it string then convert to int like this:

int y= Convert.ToInt32(a[2] + "");
//this will give 7

2 - Use Int16.Parse method

int y = Int16.Parse(a[2] + "");

a[2] is a character so I make it String because this method except string.

Answer 3

ooh ok, Thank you very much AJ.

Answer 4

And what should I do to make it 7?