Changing the value of a variable without using a temporary one

Question

Write a function that swaps the values of variables without using temporary variables.

int a=17;
int b=64;
cout << "Input: " << endl;
cout << "a = " << a << endl;
cout << "b = " << b << endl;
a+=b;
b-=a;
a+=b;
b=b-b*2;
cout << endl;
cout << "Output: " << endl;
cout << "a = " << a << endl;
cout << "b = " << b;
return 0;

What other ways are there to solve this problem?

Answer 1

Use std::swap

https://en.cppreference.com/w/cpp/algorithm/swap

Answer 2

https://code.sololearn.com/cC10lUKC38Si/?ref=app

You can also check this
Swap in a single line...

Answer 3

such a simple solution, wow, I can't wait to start learning c++