WHY IS THIS WRONG?

Question

def my_min(*x):
for i in x:
for a in x:
if i < a:
continue
elif i >= a:
return my_min(x[a:])
return i

print(my_min(8, 13, 4, 42, 120, 7))

Answer 1

here is a solution with a simple for loop that is working:

def get_min(nums_tup):
min_ = a[0]
for num in a:
if num < min_:
min_ = num
return min_

print(get_min((18, 4,32,10,1, -1,55,100,11)))

Answer 2

FF9900 ,

can you please enlighten me why

> ox = 2^32 is used? the expression results in: *34*

and i also would like to ask why the values in the tuple

> a =(184, 41,320,100,99, 1111,55,100,110)

is giving a result of *34* as the minimum element, even is this elemrnt is not existing?

Answer 3

FF9900 ,

despite of the correction you made in the code, the error remains if the numbers in the tuple are greater than 2**32.

Answer 4

Ahhh yes, much simpler, many thanks :)

Answer 5

FF9900 be careful translating from C into Python. Whereas C has limited integer range, there is no definitive MAX_INT in Python 3.

Answer 6

👍

Answer 7

Yep, in the tuple. I figured out whts wrojg though i think

Answer 8

I know that a min() function exists, i just wanted to sus out what that actually was—->

def my_min(*x):
for i in x:
for a in x:
if i < a:
continue
elif i >= a:
i = a
continue
return i

print(my_min(8, 13, 4, 42, 120, 7))

Answer 9

This works

Answer 10

I believe