I can't understand the this error

Question

import java.util.ArrayList;
import java.util.*;
import java.io.*;

public class Main {
public static void main(String[ ] args) {
Scanner scanner = new Scanner(System.in);
int tot=0;int avg=0;
ArrayList<Integer> evennums = new ArrayList<Integer>(3);

while(evennums.size()<3){
int num = scanner.nextInt();
//your code goes here
tot = tot+num;

}
avg=tot/3;
System.out.println(avg);

//calculate and output the average integer value

}
}

Answer 1

Your while loop is infinite loop.
Where is you using ArrayList in your program? You just initialized, never updating it so its size remiains 0 forever..
Instead add input to list or use a counter variable instead of list.size()...
hope it helps....

Answer 2

But i used the arraylist named as evennums... And how to you know it's infinite loop

Answer 3

You are posted same code..!
See
ArrayList<Integer> evennums = new ArrayList<Integer>(3); //you declared arraylist here, initially size is 0. No elements added yet.

while(evennums.size()<3){ // here it is condition now is while( 0< 3){ // true
... In loop here, you never adding to list so size still remains zero.
}

So next iteration,
0<3 true
.
.
This loop never stops since condition 0<3;

Instead add to list by
evennums.add(num); in loop

Else, no need list.

Take counter

int count = 0;

while( count < 3 ){
int num = scanner.nextInt();
tot += num;
count++;
}

Answer 4

while( evennums.size() < 3 ) {
What is size() each time returns in loop? It's always zero..

Where are you using list?

Answer 5

This one correct or not
import java.util.ArrayList;
import java.util.*;
import java.io.*;

public class Main {
public static void main(String[ ] args) {
Scanner scanner = new Scanner(System.in);
int tot=0;int avg=0;
ArrayList<Integer> evennums = new ArrayList<Integer>(3);

while(evennums.size()<3){
int num = scanner.nextInt();
//your code goes here
tot = tot+num;

}
avg=tot/3;
System.out.println(avg);

//calculate and output the average integer value

}
}