How can I go back to a line in my code if a condition is not met

Question

Card_type = input("Do you use an Amex or Visa card? ")
if Card_type == 'Visa' and 'Amex':
print('accepted')
else:
#here i need a code that will take me back to line 1
Print(line 1)

Answer 1

Austin Gregory ,

as Snehil Pandey already mentioned, we need a loop that can repeate a part of the code if a condition is not met or not. the input() function needs to be inside the loop.
if the condition is met, we can exit the loop by using `break`.

[EDITED]:
> please also check the conditional statement in: `if Card_type == 'Visa' and 'Amex':`.

Answer 2

Austin Gregory ,

sorry, i was wrong with my suggestion to use `or' operator. i did not make sufficient test cases.

anyway. i have made a a test code for you, using the `and` operator.
> input: `Visa` -> shows ok
> input: `Amex` -> shows not ok

so the best way would be to use the in operator:

while True:
Card_type = input("Do you use an Amex or Visa card? ")
#if Card_type == 'Visa' and 'Amex':
if Card_type in ['Visa', 'Amex']:
print('accepted')
break
else:
#here i need a code that will take me back to line 1
print('wrong input')

Answer 3

Sorry for late response:
I'm having some issues with sololearn
https://code.sololearn.com/cdDlV4ibb1Ae/?ref=app

Answer 4

Hi Austin Gregory :)
Q/A is like a public forum. Anyone can see your number. Therefore, its not a good idea to post your number publicly.

To prevent yourself from any possible spam, you should remove your number.

Answer 5

replace if with while

Answer 6

Lothar using the OR operator will allow intake of anything else inculding the already defined data's

Answer 7

Lothar can we connect on WhatsApp?

Answer 8

Sandeep thanks for the advice sir

Answer 9

Can you do it so i can see

Answer 10

It worked out sir, you really deserve the pro badge

Answer 11

I am new in progrmming ned help for my first program

Answer 12

Lothar here's my contact [phone] hit me up sir