I need a solution

Question

A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array expected where expected[i] is the expected height of the ith student in line.

You are given an string with integer heights representing the current order that the students are standing in. Each heights[i] is the height of the ith student in line (0-indexed).

Return the number of indices where heights[i] != expected[i].

Input Format

The input format will be in string

Constraints

1 <= heights.length <= 100 1 <= heights[i] <= 100

Output Format

The output format will be in a integer

Sample Input 0

114213

Sample Output 0

3

Explanation 0

heights: [1,1,4,2,1,3] expected: [1,1,1,2,3,4] Indices 2, 4, and 5 do not match.

Sample Input 1

12345

Sample Output 1

0

Explanation 1

heights: [1,2,3,4,5] expected: [1,2,3,4,5] All indices match.

Sample Input 2

51234

Sample Output 2

5

Answer 1

Rajeshwari. S ,

just some small modifications are needed:

# if we take `114213` as input.
a = list(map(int,list(input()))) # `split()` does not help to get digits from the number, we need `list()`. output is: [1, 1, 4, 2, 1, 3]
^^^^
#b = map(int,a) # not required

res=sorted(a) # use var `a` (list) to create sorted list

Output = [index for index, elem in enumerate(res) if elem != a[index]]
print(len(Output ))

Answer 2

What have you tried? link us your code so we can help you out!

Answer 3

https://code.sololearn.com/cBHY8q12aone/?ref=app

Answer 4

Rajeshwari. S
Input is a single word of digits. So input().split() does nothing..
Instead use list(input()) #list of characters.