Help with understanding the solution.

Question

Hello sololearners.
Given the code:
static int Func(int a =3, int b = 7, int c = 6){
return a+b*c;
}
static void Main(string[] args)
{
int a = 4;
int b = 5;
int c = 2;

Console.Write(Func(c, b)); // it's 32
}
Please, can anyone explain why the answer is 32? How the main method calls the Func so we get 32? Please?

Answer 1

Func(c,b) is the same as Func(2,5)
In the Func method, you have optional parameters. It has 3 parameters, but you only gave 2 (i.e. 2 and 5).
So the third parameter by default is 6, because int c = 6.
So Func(2,5) is actually Func(2,5,6) which is 32 😀

Answer 2

When called by main method the arguments are a=2 (replaces default value), b=5 (replaces default value) and c=6 (still default value, because no other value is passed).
It returns 2+5*6 then, which results in 32:
5*6=30 (calculated first, because of the precedence of * over +)
30+2=32.

Answer 3

@Elena If you want, you can insert your code into your question so others can run it.
E.g.
https://code.sololearn.com/ci0rLWK9m3Bx/?ref=app

Answer 4

@Aditya, I read your post. Should I downvote now?

Answer 5

Your most welcome ^^

Answer 6

Oh, thank you all. So very helpful and quick. I feel like hugging you! 😊

Answer 7

@Jafca, Thanks, new feature. Good to know ^^

Answer 8

@Mike, you can post your code here so we could help you.

Answer 9

Value passing (2,5) and third value is default as (6), and calculation goes on as 2+(5*6)=2+30=32

Answer 10

The names of variables don't mean anything in different contexts. In your case, you passed 2 parameters to the function. They will replace the 2 first parameters. Third one will be defaulted. 2 + 5 * 6 = 32. The variable names were only used to confuse you.

Answer 11

In Func c - is a (2), b - is b (5), c is the default (6)

Answer 12

when I try to declare a variable as a parameter IE. Func(a=3) it says ; expected

Answer 13

hello