What is the output of the following code and Why:

Question

x='a'
if(x<'c'):
x+='b'
if(x>'z'):
x+='c'
print (x)

Answer 1

The ascii value of 'a' is less than ascii value of 'c'
x becomes 'ab'
'ab' > 'z' is false (it checks by ascii value of first character)
Therefore x remains 'ab'

You can check ascii value by ord()

Answer 2

You can find the output by **running** the code: Go to Code section, click +, select the programming language, insert your code, click Run.

Check the spelling of print()

Answer 3

The output would be

ab

Answer 4

You can remove the other print() when you have understood how the code works

Answer 5

put a print() in each if-block to see which one is executed

Answer 6

Ya as 'a' is the first character

Answer 7

Output is ab But How ??? It must be 'abc'

Answer 8

Ok I understand it check only a of 'ab' in condition x>'c'

Answer 9

Thanks,I understand but i only want to print the x value at last

Answer 10

Ok

Answer 11

Purva Bharadiya it only check the value of a in 'ab'.m'I right?