#include <iostream> using namespace std; int main() { for (int x=1; x<10; x++) { if (x==2){ continue; } if (x==5){ break; } cou

Question

How many numbers will the following above loop output?

Answer 1

1. Your code is incomplete.
2. You can run it yourself in the code playground, and verify the result.

Answer 2

cou?

Answer 3

Alex Boso Nzaphila
As Tibor suggested, if you ran the code in playground you would have the answer to your question.

Answer 4

Continue; omits the following statement

Break; immediately exits the statement where it is

Answer 5

If you add a line like
cout<<x<<endl;
Then you'll get the output like:
1
3
4

Answer 6

for(int x=1;x<10;x++) {
if(x == 2) {
continue;
}
if(x == 5) {
break;
}
cout << x << endl;
}

Answer 7

5

Answer 8

cout<<x<<endl;
}
}

Answer 9

It's not supposed to be run, its a question asked.

Answer 10

It's incomplete code, so how it would be declare loop output.

Answer 11

Three if we don't look at the syntax mistakes :)

Answer 12

Thanks Rob