What is the output this code ?

Question

#include <iostream>
using namespace std;
int abc(int a){
switch (a)
{
case 0: cout<<"one";break;
case 1:cout<<"ten";break;
default : cout<<"error";
}
return 0;
}
int main(){
int c=3;
c--;
cout<<--c;
cout<<abc(c);
}

Answer 1

your function return type is int so it must be return a value
return a or any integer value or make it void abc(). inside main you have declared one variable c which has value 3then ,--c which will be decreased by 1 after that in cout you print the value of --c this pre decrement operator will again decrease value by one so
1 will be printed o. screen next in last cout statement you calling function abc and pass c value as argument abc(1) in switch the case which have 1 will be executed so second case< ` ten `>will print it returning garbage value becz u using cout first ten printed then this cout<< cout<<<`ten`> which is garbage to avoid this remove cout where u calling function just write like this

abc(c)

Answer 2

I corrected it. Thanks

Answer 3

isming nima