Answer 1

https://code.sololearn.com/WTG8n36eR9SJ/?ref=app

Answer 2

https://code.sololearn.com/cgfc7U5PEK62/#java

my try

Answer 3

My humble attempt in java

https://code.sololearn.com/cw8EUZejbyu4/?ref=app

Answer 4

Thanks for showing a really good example of a challenge that is clear and concise.

I actually enjoyed thinking about this challenge. It shows that a factorial result can be validated by dividing each successive term, starting with dividing the input by 2, then dividing that quotient by 3, then 4, and so on, until yielding 1 as the final quotient. As long as each successive quotient yields a whole number where the final whole number quotient is 1, the factorial is valid and the factorial base will be the divisor used to yield 1 as the final quotient.

I'll try to submit a code sample using lambda expressions in one of the languages later.

Answer 5

My code
https://code.sololearn.com/Wh7SBzgr3iYi/?ref=app

Answer 6

my try in Python..🐍
https://code.sololearn.com/cb463CFzBDx5/?ref=app

Answer 7

See my code -

https://code.sololearn.com/cI1uIwQr7un0/?ref=app

Answer 8

Here's the code:

https://code.sololearn.com/chK39KCTDQ0K/?ref=app

Answer 9

here
https://code.sololearn.com/c1CJMD2wAw0a/?ref=app

Answer 10

Here's mine.
https://code.sololearn.com/cjalTTzNjc60/?ref=app

Answer 11

https://code.sololearn.com/ccbE3mcoq4N1

Challenge: Reverse Factorial

Sol:
C++

#include <iostream>
using namespace std;

int main() {

int num,cur,res;
cin>>num;
if(num == 1)
cout<<"Output: 0! or 1!";
else if(num > 1)
{
res=2;
cur=1;

while(num>cur)
{
int fac=1,temp=res;

while(temp)
fac*=temp--;

cur=fac;

if(num == cur) break;

res++;
}

if(num == cur)
cout<<"Output:"<<res<<"!";
else
cout<<num<<" is not a reverse factorial. ";
}
else cout<<"Please enter positive integer number.";

return 0;
}

Answer 12

I did it!!!
tried whole day and now at midnight I got success,
so happy to share it...

https://code.sololearn.com/c440IK1e94Cx/?ref=app

Answer 13

Here is my try....

https://code.sololearn.com/c5WBuEQAbevI/?ref=app

Answer 14

You can also refer to:

https://www.sololearn.com/discuss/548095/?ref=app

Answer 15

@ace nope. read again.0 if not a factorial n if n!

Answer 16

Java:
https://code.sololearn.com/c0BVJZcyO3cY/?ref=app

Answer 17

https://code.sololearn.com/cPPwmEB4B4R9/?ref=app

Answer 18

Here is my version.

https://code.sololearn.com/cPfffpGHj4nY/?ref=app

Answer 19

my practice on python https://code.sololearn.com/csv2TWmr2BKn/#py

Answer 20

I tried but couldn't do better than this...
kindly help me in solving it...
https://code.sololearn.com/cQE7cWDIpIPf/?ref=app