The output for this code is 11. Can anybody explain the reason

Question

template class<T>
void f(T){
int i= 0;
cout<<++i;
}
int main()
{
f(2);
f(4.2);
}

Answer 1

the output should be 11 because you can see i is always initialised with 0,so the function f will always output 1 irrespective of the passed parameter.

Answer 2

it should be 11,why will the output be in different lines as no \n or endl is used.

Answer 3

cout doesn't add endline by itself, you have to explicitly specify it.
cout << ++i <<endl;

Answer 4

i will be initialized to 0 each time function will be called so thats two times 1
gets printed

and as no endl or /n therefore no new line .......isnt it simple

Answer 5

ohkay..so it must be
1
1
and not "11" !
I got confused with this

Answer 6

f() is called twice ..so I think it should be in different lines