ARMSTRONG NUMBER

Question

can someone pliz explain to me how this armstrong number function in java works.its the latest code on my profile

Answer 1

hi
from right to left of a number extract digits
n%10 rest is n//10
for every digit n: n*n*n add to sum

if(3*3*3 +5*5*5+1*1*1) ==153, 153 is an armstrong number

Answer 2

class ArmstrongExample{
public static void main(String[] args) {
int c=0,a,temp;
int n=153;//It is the number to check armstrong
temp=n;
while(n>0)
{
a=n%10;
n=n/10;
c=c+(a*a*a);
}
if(temp==c)
System.out.println("armstrong number");
else
System.out.println("Not armstrong number");
}
}

Im trying to understand how it works