what??

Question

num= 7
if num>5:
print("ok")

if num==7
print("👌")

why is ok correct??

Answer 1

The correct code will be something like this...

num= 7

if num>5:
print("ok")

if num==7:
print("7") #use any string or no. instead of 7

The 👌 u used cannot be printed in SL...

Output:
#ok
#7

Answer 2

because num is more than 5. so the following condition is executed.

Answer 3

this due to precedence because first condition is true it prints ok now i think it never reach to the next condition but i think that would happen when you use a elif condition. i dont know python a lot, but generally i think its because of the precednce of conditions.

Answer 4

th numb is also 7
i mean
num==7
is true isn't it?