Why the output of this code is 16?

Question

Int a=2, b, c;
b=++a;
c=++b;
a=b*c;
Cout<<a;

Answer 1

I understood))

Answer 2

int a, b;
a = 2;
cout << a << endl;
b = ++a;
cout << a << endl;
cout << b << endl;

Output:
2 //A
3 // A
3 // B

By using the ++x prefix on an interger, you also increase the number of the original interger.
B becomes 4 after you assign C with (++B), because the compiler first adds 1 to 3, then assigns B to C.
In other words, A is actually 4 * 4.

If you want B to stay a 3, then use (C = B + 1;), which gives C a number 1 number larger than B's, while keeping B as a 3.

Answer 3

preincrement