+ 9
[challenge] how many fishes does Tom have?
Tom decides to sell all his fishes he sells: 1/2 of all his fishes and 1/2 fish 1/3 of the rest and 1/3 fish 1/4 of the rest and 1/4 fish 1/5 of the rest and 1/5 fish now he still has 11 fishes Tom would never be able, to kill even one of his fishes. How many fishes did Tom have at the beginning? find out with a program. Have fun
13 Answers
+ 12
some of you say, it is too easy. It is indeed.... .
but it is a special case of
program follows brain ( for beginners )
+ 8
This is a simple mathematical puzzle;
Suppose the number of fishes he has at the start is x.
The first time he sells, he has (0.5x - 0.5) fishes left.
Next, he sells 1/3 of his fishes + 1/3 of a fish, meaning he has (2(0.5x - 0.5) / 3) - (1/3) fishes left. This is getting complicated, so let's call that number y.
Next, he sells 1/4 of his fishes and 1/4 of a fish. That would mean he has 3y/4 - 1/4 fishes left. This is z.
Finally, he sells 1/5 of his fishes, and 1/5 of a fish. So, he has 4z/5 - 1/5 of a fish.
Which we know is equal to 11.
Now, to solve the equation backwards...
4z/5 - 1/5 = 11
4z = 56
z = 14
3y/4 - 1/4 = 14
y = 19
2(0.5x - 0.5) / 3) - 1/3 = 19
x = 59
Therefore, he started with 59 fish.
//QED.
😉
[Edit] I could write a program if you wanted me to, but there's no point.
+ 6
print(((((11+1/5)*5/4+1/4)*4/3+1/3)*3/2+1/2)*2
+ 5
Use the branching method, it will be very helpful
+ 5
Yeah, here's my complete search solution;
https://code.sololearn.com/coqIKaj0grI8/?ref=app
+ 5
https://code.sololearn.com/ck1oyPDVpIS5/?ref=app
+ 4
This is hmmm... kindergarten drill not a challenge! besides I don't understand your question
+ 4
@Batman Actually, if you solve it mathematically, there is no point writing a program. Let's say you have an algorithm for tic-tac-toe where you cannot be beaten if you follow it. If you want to create an unbeatable program, you'd just give it to the computer, instead of complete searching every single possibility every turn. Hence, math over program over brain. 😉
+ 4
@ Batman
(( as u love patterens ))
I DERIVED 4 INTERESTING THINGS OUT THERE FROM THIS CHALLENGE
** taking initial case with 59 fishes as 1 //
✔ The casewhen the no . of fishes reaches 1
✔ The case when it gets the LAST +ve Value
✔ For which cases No. Of Fishes
are PERFECT - INTEGERS
✔ a nice " PATTERN " >>>>
CAREFULLY LOOK ::::::
if for case 'x' no. of remaining fishes is 'y'
for case 'y' no. of remaining fishes is 'x'
https://code.sololearn.com/c0dGHZX37F8q/?ref=app
+ 3
no loop...
one liner...
😂😂😂😂😂
https://code.sololearn.com/cK0s9J6Je97w/?ref=app
+ 3
class A{
public class void main(String args[]){
int x;
x=11;
x=x+(4*x/5)+1/5;
x=x+(3*x/4)+1/4;
x=x+(2*x/3)+1/3;
x=x+(x/2)+1/2;
System.out.println(x);
}
}