If --x and x-- are different arguments, then why do they appear to yeild the same output when ran in Code Playground?

Question

https://code.sololearn.com/cELUWa8ZixVZ/?ref=app

Answer 1

try replacing x-- with x=x-- ;
& when u write ---x replace it with x=--x ;
//U will get the difference

/*
the difference is not visible another line , when we we assign this value to a different variable or its remain unassigned(just incremented or decremented)
*/

Answer 2

right @Vadim 👍

Answer 3

try this:

int x = 0;
System.out.println(x++);
x=0;
System.out.println(++x);

Answer 4

In this case there is a difference:

int x = 3;
while(x > 0) {
System.out.println(x--);
}

int y = 3;
while(y > 0) {
System.out.println(--y);
}

See also: https://www.sololearn.com/learn/Java/2141/

Answer 5

maybe this helps you to understand 😊