Can someone explain this please!!

Question

def boo(a,b):
a+=2
b-=2
y=foo(a,b)
return y
def foo(a,b):
y=(a+b)/2
return y
result=boo(4,6)
print(result)

Answer 1

Walk through it step by step, write it down on paper if that helps.

First, the function boo is called. Variable a is incremented by 2, variable b is decremented by 2, and these new values are passed into the function foo

foo adds variables a and b together, divides the sum by 2, and returns that number to boo, which then returns that number to the print function

Answer 2

#There is defined function boo which can take two arguments to input, so when we have row with code result = boo(4, 6 ) we call it with arguments 4 and 6
#boo(4, 6) where a = 4 and b = 6
#so, then a+=2 which means a=a+2 --->a=4+2=6
#b= b-2 - - ->6-2=4
#so now a = 6 and b = 4
#That was this part of code:
#def boo(a, b):

# a += 2
# b -= 2
#Now we have this part:
#y = foo(a, b)
# return y
#So, we call function foo with our a and b which means:
# foo(6, 4)
# y= (6 + 4) / 2 = 5.0