How to print sum of all numbers in the any digit number in python?

Question

How to print sum of all numbers in any digit number of user input in python
like 👇
123 = 1+ 2+ 3
=6
67890
6+7+8+9+0
=30

Answer 1

a=int(input())
print(sum([int(x) for x in list(str(a))]))

Answer 2

n=123;
sum=0;
while (n>0)
{
d=n%10; //for make the digit single

sum=sum+d; // for adding the digit which we get from d variable.

n=n/10; //to keep on making dividing the digit.
}

Answer 3

Input from user

Answer 4

#how to sum all the digits of a given number
num=str(input('Choose a number:'))
i=len(num)
sum=int(num[i-1])
while i>1:
i-=1
sum+=int(num[i-1])
print ("the sum of all the digits in",str(num),"is",str(sum))

Answer 5

How to do that in JavaScript?

Answer 6

n=input('enter the digits you want: ')
p=n.split()
q=0
for i in n:
q=int(q)+int(i)
print('sum of digits is: ',q)