Do Conditional Operators have precedence?

Question

i come across a question in submissions about these operator's != , || , && having precedence in java.

i know that maths operators do but i have never heard of conditional operator's having them before?

i choose false but apparently i was wrong?

Answer 1

yes
/*i submitted a good quiz on that but was declined saying "so many quizzes of this type already exist" 😂*/

Answer 2

yaa we have that type of quiz in C++
guess what I just played ...😂😂😂
cout<<!(1||0&&!1)
//output :- 0

Answer 3

true||false&&false

//answer will be true , but most ppl do it as false 😅
//so i made this as quiz

Answer 4

it will be treated as true||(false&&false) ..... true||false ... ie true
//bcz precedence of && is greater than that of ||
@David

Answer 5

http://www.cs.bilkent.edu.tr/~guvenir/courses/CS101/op_precedence.html

Answer 6

@Cool Coding Thank you very much! i do wonder though why i have only just learned this now. 🤔

Answer 7

@ Gaurav did you make code quiz about it? if so can i have a look at it ? 😀

Answer 8

Thank you very much Gaurav thats perfect 👍👍👍👍

Answer 9

@ Gaurav can you explain to me how i should read true||false&&false i have never seen this before whats going on with me haha 😨 thanks

Answer 10

🤔 now im unsure what answer is right is there anyway to see step by step execution of this exspression? thanks

Answer 11

true||false&&false..... The answer is false.
The checking starts from left to right and not according to precedence.
While checking from left to right the execution takes place in this way.... 👇
(true||false)&&false
true&&false
false

I took help of parentheses just to explain you... Thank you.