Whats the reason behind this output?

Question

My sister was typing this and found this output, then she called me , and asked "What is this in the output?"

Actually she missed out the quotes while declaring the character. But even though the output should not be this.

https://code.sololearn.com/cMf45JfPsXkx/?ref=app

Answer 1

This is a random garbage value that has been assigned to a and b. Without the quotes, a gets a's value, which was not assigned yet. and results in a garbage value. Thus you get the weird output. Similar things happen with b, but since b is a char, it gets restrained to an ASCII value...

Answer 2

Before initializing i.e. allocating a value to a variable it has its own value which is called as garbage value which is happing with int a. And as I think b is pointing to null. So to get proper output replace
int a = with any number
char b = 'any character'

Answer 3

I'm not sure that b is having garbage value as it displays nothing . So , either it's value is null or it's pointing nowhere that means no value is there .
https://stackoverflow.com/questions/25573435/what-is-the-default-value-of-char-in-c

Answer 4

I'm not sure that b is having garbage value as it displays nothing . So , either it's value is null or it's pointing nowhere that means no value is assigned to b.
https://stackoverflow.com/questions/25573435/what-is-the-default-value-of-char-in-c

Answer 5

ooh thanks :-)
the StackOverflow's link helped

Answer 6

no, b doesn't shows anything, that's what I'm curious about. you can try removing the statements consisting a;

Answer 7

@Hrishikesh but why doesn't b stored any garbage value

Answer 8

Oh, thanks @Ace

Answer 9

Can anyone of you, answer this question..?
https://www.sololearn.com/Discuss/1063293/?ref=app
Thanks in advance :)