char *a ="coding"; char *b=(++a)+3; cout << b;???

Question

i don't understand this, can someone give some explanation?

Answer 1

you're right saeid, i think it writes cout<<*b;

Answer 2

@vikas i'm sure that i get at least one run from this code and the answer was "n" ;)

Answer 3

if 'cout<<b' the output is "ng"
but if 'cout<<*b' the output is "n"

Answer 4

all these *chars acts as an array the ' *a ' initially indicates/ points the first charactr of the string and as the *a gets incremented the memory address is increased. as like in arrays.

also these are defined in chars so output is also a char not a string so 'n' is the right answer

Answer 5

the output is "ng" bcuz you assign the address of n to b. and when you print b then it will print from n to last character of the string i.e. g.

Answer 6

hey @nima,
before saying anyone wrong.....first you should prove yourself correct............can you please copy this code and run it on this app sololearn.............you'll get your ans

Answer 7

b points to a + 4 implies cout << b prints 'ng'

Answer 8

the output is "n" because you assigned "a" from second character(++a) to end to "b" and you want print a character in the index "3" from this "oding", that is 'n'

Answer 9

you're wrong @vikas