I want help with this code

Question

The problem is in the program itself.

https://code.sololearn.com/c5LeZ4c0Lykz/?ref=app

Answer 1

#include <iostream>
#include <string>

using namespace std;
int main()
{
string str;
cout<<"Enter a string: "<<endl;
getline(cin, str);
for(int i=0;i<str.length();i++)
{
str.at(i)=(str.at(i)=='0'?'1':'0');
}
cout<<str;
return 0;
}

//Now U will be thinking U have seen it somewhere
//well everything is near U , U just need to think how to use them smartly

Answer 2

how about taking that binary number in a String & then replacing 1 by 0 & 0 by 1
1 more thing 0%10 will be 0 , not infinity
//for correcting your code ,just make a case for 0 also using if , as your loop will not work for 0 as input
//hope it helps 👍

Answer 3

your code couldn't work for these two reasons:

1) you gave a condition of while (n!=0) which means when you enter zero as your value for n the loop wont execute as the condition evaluates to false

2) the other problem is a bit complex, because when you try to enter value for n as a binary number like 01101 or any other that begins with a 0, cin doesn't read in input in this way as an integer number doesn't begin with a zero unless it's only zero itself so when your binary number is 011 it will only read eleven.

I couldn't get around that but I tried this :

#include <iostream>

using namespace std;

int main()
{
long long n;
cout<<"Enter a binary number: "<<endl;
cin>>n;
int rem=0;
string num="";

do
{
rem = n%10;
n=n/10;
if(rem==1)
{
num=num+"0";

}
if(rem==0)
{
num=num+"1";
}
}
while(n!=0)
;
cout<<num;
return 0;
}

Answer 4

Gaurav can you please post the code. I tried but i am not getting it correct.

Answer 5

yeah thanks man👍