Simple linked list, is element fumction! (m && n)

Question

Why do you use "m && n" instead of just "n" for comparison in this case of a is element function of a simple linked list?

int list_iselem(list m, int n) {
while(m && n != m->element) {
m = m->next;
}
return (m && n == m->element);
}

Answer 1

m is your pointer. If it is null, it doesn't point to anything and is also 0/false. If it does point to something, it is non-zero or true.

Answer 2

Oh thank you, that makes sense. I guess I confused the prioritys there too. != has the higher priority than && so if the left statement is unequal and the right is true, the loop gets executed.