seeing which number in an array is larger

Question

Normally I could sort arrays easily, but today it's giving me some weird results with the location number with i. Yet it works when using numbers rather than symbols.

#include <iostream>
using namespace std;

int main()
{
int i = 0;
int size = 0;
int list[10];
for (i; i<10; i++)
list[i] = i;

for (i=0; i < 10; i++)
{
if (list[i] > list[i+1])
{
cout << list[i] << " " << list[i + 1] << endl;
cout << "The array is not sorted" << endl;
break;
}
else if (i != 9)
continue;
else
cout << "The array is sorted" << endl;
}

for (int i = 0; i < 10; i++)
{
cout << list[i+1] << endl;
}
// cout << "The array is sorted" << endl;
system("pause");
return 0;

}

It should be checking the first number with the second, but it's checking the last number and a random 3. If you flip the greater than symbol to lesser than, you get the right numbers. I have no idea why this is happening today. I have done this before, but the compiler is making up it's own rules.
I'm using a sort function from the algorithm library, but I am not including it in this question.

Answer 1

your code seems to check the array that is sorted or not

your array has 10 elements and in c++ your array indexes start from 0 to 9

so the line
else if (i!=9)
must be
else if (i!=8)

and in 3rd for in your code
cout << list[i+1]
must be
cout << list[i]