i have overloaded two Funtions one with int parameter and the 2nd with A float one..and..:

Question

#include <iostream>
using namespace std;

void print(int a){

cout<<a;

}

void print(float b){

cout<<b;
}

int main()
{

print(1.6);

return 0;
}

could someone tell me why the 1.6 is not printed? isnt it a float number?

Answer 1

If you write it like this you will get warning. Compilator doesn't know if you want to parse it to int or to float. You need do declare a variable float f=2.6 and then print it.

Or make it like this: print((float)1.6);

Answer 2

This is because by default 1.6 is considered a double (not float) and it becomes ambiguous which version to call
It can be resolved by using any of the following ways :

1. Change float to double in function prototype
void print(double b)

2. Pass 1.6 by type casting as float
print((float) 1.6);
Or
explicitly defining 1.6 as float
print(1.6f);

3. Declaring as float and passing
float a = 1.6;
print (a);

Answer 3

I think a float number can be explicitly defined using 1.6f
This tells it that 1.6 is a float

so print(1.6f) should work

Answer 4

Bishal On the second example you gave, 1.6f does NOT cast 1.6 from double to float. It defines it to be a float, so it is faster than a cast.

Answer 5

Thanks for pointing out Bebida Roja :) . *Corrected

Answer 6

Bartosz Pieszko Thank you alot now its all clear👍

Answer 7

Bishal Sarang thank you