I had to make a condition that the input sequence ends in a character (0) so that the program knows when to end. Avoidable?

Question

https://code.sololearn.com/c3wo4IkKG96G/?ref=app

Answer 1

You can do len(input) and do it without 0.

Of course it is needed to rebuild this sample of code.

Answer 2

The nested while is not working well. It want to have access to not existing element of string. You have to check length == 0 first (before getting to index of array).

The if/while statements works from left to right: on the first statement it causes error and not check second. If you change them then it first check the length and later try check the index of array.

Answer 3

thanks

Answer 4

By the way try to code:
a != b
Instead of
not a == b

Answer 5

thanks a lot!
I got it working!

Answer 6

How it works: aaabbc0 becomes a3b2c

Answer 7

input = input() #input any sequence of letters
length = len(input) #initialize length
print(length)
adress = 0 #intialize adress
compressed = str() #intialize compressed
while not length == 0: #end loop when 0
letter = input[adress] #letter to check if it repeats
compressed += input[adress] #add letter to output
nletters = 0 #reset number of consecutive letters
while input[adress] == letter: #loop for each consecutive letter
adress += 1 #increment character of string read
nletters += 1 #increment number of consecutive letters
length -= 1 #decrement length
print(length)
if not nletters == 1: #skip add number of consecutive letters if only one letter
nletters = str(nletters)
compressed += nletters #add number of consecutive letters to output
print(compressed) #print output

Answer 8

thanks! ok so why isn't this working?