[CHALLENGE] Buzz number!

Question

Buzz number is such a number which is either completely
divisible by 7 or extreme right side digit of the number is 7.

Output 1
Enter the number:63
Entered number is a Buzz number.

Output 2
Enter the number:87
Entered number is a Buzz number.

Output 3
Enter the number:186
Entered number is not a Buzz number.

Answer 1

https://code.sololearn.com/cUuwdcmUkfuL/?ref=app

Answer 2

It was not very difficult:

https://code.sololearn.com/cCYGv3CIKyWH/?ref=app

Answer 3

In ruby
https://code.sololearn.com/cfMJ898RZzcg/?ref=app

#can be submitted as an assignment
https://www.sololearn.com/discuss/1082512/?ref=app

Answer 4

here's mine😊😊
https://code.sololearn.com/caOVKSBye9Qn/?ref=app

Answer 5

https://code.sololearn.com/ctJ9vAIqSlUL/?ref=app
https://code.sololearn.com/cuKBdw1dhZe2/?ref=app
https://code.sololearn.com/cFCKmqdsZ8tO/?ref=app
https://code.sololearn.com/c21TqAVoVtAs/?ref=app

Answer 6

# Python
# number given as n

print(n%7==0 or str(n)[-1]==“7”)

Answer 7

https://code.sololearn.com/cpJsjHLK6c8r/?ref=app

Answer 8

//Java
import java.util.Scanner ;
public class Program
{
public static void main(String[] args) { int number ;
Scanner obj = new Scanner(System.in)
number=obj.nextInt();
if(number%7==0 || number%10==7)
System.out.println(number+" is buzz number") ;
else
System.out.println(number+" is not buzz") ;
}
}

Answer 9

Here's mine. I did it so that it tells the user how much the number is off by from the last and next buzz numbers.

Buzz Numbers:
https://code.sololearn.com/c13d9E2gQXNW/#py

Answer 10

//C++
// code for buzz numbers
/* buzz numbers are those which are
completely divisible by 7 or give remainder 7 */
#include <iostream>
using namespace std;

int main() {
int number ;
cin>>number ;
if(number%7==0 || number%10==0)
{
cout<<number<<" is Buzz number " ;
}
else
cout<<number<<" is not buzz number" ;
return 0;
}

Answer 11

https://code.sololearn.com/cBnhd8GNeC3G/#cs

Answer 12

https://code.sololearn.com/cy5lXTxx689V/?ref=app

Answer 13

https://code.sololearn.com/c8eRLYSCW6cr/#cs

(I'll admit that I kind of copied the % part though)