year is not defined (JS)

javascript

18th Apr 2018, 7:52 AM

Simonas Vaškys

7 Respuestas

+ 1

Create a new file, call it test.htm and just paste in this code: <html> <head> </head> <body> <script> function printTime() { var d = new Date(); var year = d.getFullYear(); var month = d.getMonth(); var day = d.getDate(); var hours = d.getHours(); var mins = d.getMinutes(); var secs = d.getSeconds(); var msecs = d.getMilliseconds(); var monthsArr = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']; document.body.innerHTML = year+"/"+monthsArr[month]+"/"+day+"<br/>"+hours+":"+mins+":"+secs+":"+msecs; } setInterval(printTime, 1000); </script> </body> </html> Save and open it in browser. If you'll need more explaining about something please ask :)

18th Apr 2018, 10:50 AM

Luigi

+ 6

https://code.sololearn.com/W2zqv2zPPA32/?ref=app The month names being returned should be a String as it is returning some kind of object ( I believe) and I added a p tag to display the output. I also moved it all to the script tag and saw that it worked that way.

18th Apr 2018, 8:02 AM

Tarantino

+ 1

Thank you, guys 🤗

18th Apr 2018, 10:35 AM

Simonas Vaškys

But why u write this whole code in html but not in JS? And i want that month will be displayed as April not 3

18th Apr 2018, 8:09 AM

Simonas Vaškys

Here's a simple implementation of the concept. Hint: return statement inside a function will stop the function itself and output (or return) a value to the caller, so use it until you know that that particular function must return a value. function printTime() { var d = new Date(); var year = d.getFullYear(); var month = d.getMonth(); var day = d.getDate(); var hours = d.getHours(); var mins = d.getMinutes(); var secs = d.getSeconds(); var msecs = d.getMilliseconds(); var monthsArr = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December']; document.body.innerHTML = year+"/"+monthsArr[month]+"/"+day+"<br/>"+hours+":"+mins+":"+secs+":"+msecs; } setInterval(printTime, 1000);

18th Apr 2018, 8:22 AM

Luigi

No problem! 👍

18th Apr 2018, 10:41 AM

Luigi

- 1

umm, i've tried this, but year is still not defined..

18th Apr 2018, 10:45 AM

Simonas Vaškys