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Help understanding the answer to this python question
What does this for-loop do? Input: arr = [1, 2, 3, 4, 5, 6] i = 0 for _ in arr: del arr[i] i= i+1 print(arr) Answer: Deletes the elements in the even positions
7 Respuestas
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iteration 1 -> i = 0 -> arr = [1,2,3,4,5,6] -> arr[0] = 1 -> del 1 -> arr = [2,3,4,5,6]
iteration 2 -> i = 1 -> arr = [2,3,4,5,6] -> arr[1] = 3 -> del 3 -> arr = [2,4,5,6]
iteration 3 -> i = 2 -> arr = [2,4,5,6] -> arr[2] = 5 -> del 5 -> arr = [2,4,6]
Note: The meaning of "_" in Python is that it stores the last value in the interpreter. But the loop also runs fine if you use your classic "for x in arr:"
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WeW confused me a bit nice one.
here _ is iterating variable, arr is iterable object so at start of for loop _ holds value of 0 th index or 1st element
then it deletes ith element as it's i=0 it deletes 1
now 2 is at 0 th index i is incremented by 1 so in next iteration _ has to hold value of 1st index element hence _ = 3 as now array starts with value 2 now i is 1 so delete statement will delete 3
and so on
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Try this so what I said will sound a bit logical (._.")
arr = [1, 2, 3, 4, 5, 6]
i = 0
for _ in arr:
print (_)
del arr[i]
i= i+1
print(arr)
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this makes sense!! Thank you so much :)
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Your questions are always so..tricky. I like to solve them always !!
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thank you!! @johannes
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Great! There’s lots more where that came from lol