How it works?

Question

Hello!
Why does the code print '222'? How it works?

cm = [lambda x: i*x for i in range(3)]
for m in cm:
print(m(1), end='')

Answer 1

To me it looks like your cm should be equivalent to:

cm = [
lambda x: 0*x,
lambda x: 1*x,
lambda x: 2*x
]

but Python is making it equivalent to:

cm = [
lambda x: 2*x,
lambda x: 2*x,
lambda x: 2*x
]

and I don’t know why.
If you wanted the first behavior, try defining a function with two arguments. Good luck there.

Answer 2

Yes, I, too, expected the behavior, as in your first example.

I changed the code:

cm = []
for i in range(3):
def func(x):
return i*x
cm.append(func)

for m in cm:
print(m(1), end='')

It seems to me that in this case the function variable is overwritten.
Therefore, the last value is retained:

cm = [lambda x: i*x for i in range(6)]
for m in cm:
print(m(1), end='')

result: '555555'

Very interesting)

Answer 3

What is the output
nums = [1,2,3,4,5]
print (list___(____x:x%_==0,nums))
please help