The parenthesis of Schroedinger

Question

Could someone explain this paradox to me:

def some_func():
print("Hi!")

foo = print()
if foo == None:
print ("empty1")
else:
print ("something there1")

foo = ()
if foo == None:
print ("empty2")
else:
print ("something there2")

Output :
empty1
something there2

The first empty parenthesis was interpreted as a None, but the second was interpreted as something.

Answer 1

The first condition occurs because the return of just a print() is None. For the second statement, you are assigning foo to (), which in python declares a tuple. So foo is of tuple type and not None type.