Guys what about this section of python 3 tutorial, Is it correct?

Question

I am learning python 3 from solo learn
found this...

tutorial say == have more precedence than 'or'
But...

Details:-

first
print(False == printme() or True)
when this get evaluated output is

Output:
printed
True

printme function called to evaluate the first expression which is
False == printme()

but second
print(True or False or printme())
now when this get evaluated...

Output:
True

printme() was not called to evaluate the second expression which should be evaluated first because tutorial said == have greater precedence than or.

Now run code,
shared in this post.
https://code.sololearn.com/cjKNgtn6XDco/?ref=app

Answer 1

Yeah its cool👍👍

Answer 2

ifl
Both statements don't print true...

first print

printed
True

Note:- 'printed' word

that output is totally different than the second one...
which only prints the

True

isn't?

Answer 3

Oh okay, sorry for misunderstanding your question. Good question by the way!

Why this happens is because of how the 'or' operator works, and not because of operator precedence.

-----------------------

You see, the 'or' operator returns True if either one of its inputs is True. So:

True or True --> True

True or False --> True

False or True --> True

False or False --> False

-----------------------

If you look closely, you can notice that If the first operand (left to the 'or') is True, then you don't really have to look at the second operand, because the answer is True either way.

That is exactly what Python does. If the first operand is True, it returns True without evaluating the second operand (right to the 'or').

-----------------------

In your case,

(True) or (False == printme())

As soon as Python sees True before the 'or', it knows the second expression need not be evaluated, therefore printme() is not run.

-----------------------

Hope this made sense :)

Answer 4

ifl tutorial say that == have greater precedence than or...
so in the code
second print statement
which is
print(True or False == printme())

should first print the

printed
True

But it don't

Answer 5

Just A Rather Ridiculously Long Username

both print statement should give the same result.
But they don't

Answer 6

ifl

oh thanks,
now it's making sense.

Answer 7

Vikas Gola It seems to me that the code does the right thing.... what result do you expect and how does it differ to the results you see?

Answer 8

ifl
first print statement is printing...

printed
True

and the other one...

True

check again!

Answer 9

Vikas Gola Ah yes. This is because the evaluation of the Boolean logic is left to right.

Because of operator precedence, the statement is equivalent to
true or (false==printme())
but since the left part of the 'or' is true, the right part is not evaluated.

(operator precedence and order of evaluation are different things)

Answer 10

(Just A Rather Ridiculously Long Username just beat me to it ;-) )

Answer 11

Just A Rather Ridiculously Long Username ,Both statements give the same result (true) when I execute on my phone.
As expected.

Answer 12

Vikas Gola yes, that's correct. Both statements print true.
And this is the correct answer.