Doubt

Question

Someone pls explain how this comes...??

int x,y,z;
x=2;
y=5;
z=x+++y;
printf("%d %d %d",x,y,z);

output: 3 5 7

Answer 1

The line z= x+++y; is evaluated as
z=x++ + y;
where :
x++ is post increment of x , so its value changes only after the sum of x+y is evaluated.

This is equivalent to:
x=2;
y=5;
z=x+y;
x=x+1;

Answer 2

At very first the addition is performed and then X is updated to 3 (X++) before updating X ,Z is assigned 7 .And that's all .🤗

Answer 3

See this article: https://www.sololearn.com/learn/Java/2141/

Z gets the value of x+y (2+5=7), and the x++ increments the value of x, making it 3.
Fun fact: doing z=++x+y; would return 8, as it does the calculation before the assignment. Link explains it better.

Answer 4

ok friends.....i understood what it is.......

Answer 5

btw. some examples of post and pre increment a here :-)
https://code.sololearn.com/ceYh2erq9U7y/?ref=app

Answer 6

left to right so it is considers x++ +y
since it is post increment at the time it will be 2, then incremented to 3
z=2++ +5 gives 7
so x get incremented to 3;

hence result 3 5 7