Can you fix it ? Leap year teller ?

Question

#include <iostream>
using namespace std;

int main() {

int days;

cout<<"Enter Number of days in a year\n";
cin >>days;

if(days>363)
{
if(days%400==0 || (days%100!=0 && days%4==0))
{

cout<<"Leap Year!\n";

}

else

{

cout<<"Not leap year!\n";
}
}

else
{
cout<<"Invalid Input!\n"<<"Please enter days in a year!\n";
}
return 0;
}

Answer 1

if(days==365)
cout << "Not leap";
else if(days == 366)
cout << "Leap year";
else
cout << "invalid";

// your code is applicable for year number i.e 2018 or 1966

// but you are taking no. of days as input which is causing the error.

// replace all if statements with code to prevent this error or take year no. as input.

Answer 2

i agreed with hinanawi

Answer 3

Amrit Mahendra Joseph
wow !! thanks

Answer 4

hinanawi ?

Answer 5

\/.oz ?

Answer 6

hinanawi
thanks ☺

Answer 7

hinanawi

#include <iostream>
using namespace std;

int main() {

int days;

cout<<"Enter number of days\n";
cin>>days;

if(days==365)
{

cout<<"Not a leap Year\n";

}

else

if(days==366)
{

cout<<"Its a Leap Year\n";

}

else
{

cout<<"Invalid Input\n";

}
return 0;
}

Answer 8

shehroz irfan what Sreejith said, your code should read the year number not number of days in said year

Answer 9

shehroz irfan looks good

Answer 10

I am very poor in C++, I can help with Java...

https://code.sololearn.com/cyl9chLy2vDz/?ref=app