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ANSWER PLZ
Fill in the blanks to create a pattern that matches strings that contain 3 characters, out of which the last character is an exclamation mark. r"___
quot; what ans
16 Respuestas
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(\n|.){2}\!$
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import re
num = "07987549836"
pattern = r"9"
num = re.sub(pattern, "0", num)
print(num)
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the ans of this Q's is :- ..!
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Question :-
Why "..!" ?
I don't understand
solution:-
The question is says about three letters and last one is ! so " ..!"
Two dots for first two letters.
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The answer is
x = str. replace ('!', '.')
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Please, don't help them ValentinHacker, it won't help them
0
..!
0
..!
0
Ans :
re"..!quot;
0
..!
0
..!
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The blanks is ..!
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the answer is ..!
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Ans:
r"..! quot;
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r"..! quot;
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Why "..!" ?
I don't understand
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