what does this code mean?

Question

for a in range (200):
if (a%9 or a%2 ==0):
continue
print a,

Answer 1

Venkatesh the bug is in line 2.
try it like this
if(a%9==0 or a%2==0):

Don't forget ur print(a) is not in same block as the if condition.
Here, the print(a) is technically acting as an else statement.

--With this:

if (a%9 or a%2 ==0):
continue
print a
he(python) will ignore the value of a whenever the condition of the if statement is true and print when false.

Now when a==9
a%9 == 0
a%2 == 1
and 0 or 1 != 0(condition is false)
so 9 is printed.
same goes to the other values of a that was printed.

And plz remove the comma in line 4 else python'll bite.

Answer 2

but the output is all divisible by 9
9
27
45
63
81
99
117
135
153
171
189.
.
How?

Answer 3

for a in range (200)
iterates from 0 to 200

if (a%9 or a%2 == 0):
not divisible by 9 or 2 (even numbers)

continue
Continues

print a,
outputs the value of a

Answer 4

iterates through numbers from 0 to 200, and doesn't print out even numbers or numbers divisible by 9

Answer 5

if do you want the number is not divede by 2 or 9 ... use the (), don't forget about the precedence order
ex 18
the first sentence to check because of the precedence is :
18%2== 0 >> True >> 1
18%9 >> 0 >> False
so it enters in the if and don't print
ex 27
27%2 == 0 >> False >> 0
27%9 >> 0
0 or 0 false, so it's don't enter in the if

Answer 6

code will print number from 0 to 200 which are not divisible by 2 and 9

Answer 7

simple, in fact the code does this .... it check if the number is divided by 2 (is even)... if not ... it multiple by 9.. so the output is (9*1) then 27(9*3)... etc

Answer 8

try like below, it should work

for a in range (200):
if (a%9 ==0 or a%2 ==0):
continue
print a,