Can somebody explain in detail how you get this calculation to 4? I’m a beginner thanks.

Question

Int a = 3;
Int b = 2;
B = a++;

Cout << ++b;

Answer 1

Axel Inga
first a=3 b=2 then in the next line
b=a++ here a++ follows first use then change rule (post increment operator) so b=3
then cout<<++b here it follows change then use rule (pre increment operator) so it changes b from 3 to 4.

Answer 2

Axel Inga Right 👍😊

Answer 3

Mohammad, thank you for your help. What i seam to not understand is this:
b=2 (we ignore this value right?)

b=a++ (so here it gets the same value as “a” which is 3. Right? Than, add one more because of the ++, and that would leave it to 4)
I know im wrong there, but thats how i see it and i cant seam to see it the right way. I understand the rest of the code.