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Plz answer?
please explain this code, what is the purpose of that friend overloaded function, i mean why only overload that with friend, https://www.sololearn.com/post/15495/?ref=app
2 Respuestas
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The purpose of overloading the << operator is to have an easy way of printing your object to the console. Its definition would probably look something like this:
ostream& Complex::operator<<(ostream& o, const Complex& c) {
o << c.x << "/" << c.y;
return o;
}
This way, you can write
cout << c;
in your code when you want to print the number (where c is any object of type Complex).
But as you can see, the function accesses private members, thus it is a friend. If you don't want it to be a friend function, you can make get() methods for your private variables and call those instead. E.g.
o << c.getX() ...
0
thanks.