Which topic should I study to understand this?

Question

https://code.sololearn.com/cm9aVhdl7l0r/?ref=app

Answer 1

Pointers?

Answer 2

Borislav Kalinski but it is a const char pointer, not a string object, try to call a method (e.g. "SoloLearn".length()) on it, it will not work.

That line output a copy of "SoloLearn" starting from index 5 which gives "earn" the same result can be obtained with such call:

cout << (const char*) "SoloLearn" + 5;

Please correct me if I'm wrong.

Answer 3

Thanks Ipang, Pegasus and Borislav.

Answer 4

Borislav Kalinski no need to apologize my friend, we are all here to learn, it's OK.

Cheers!

Answer 5

Strings
Because this is not a pointer.
The logic is

"something" + "something" = "somethingsomething"
"word" + 5 = "word5"
5 + "word" = error

Answer 6

Sorry I am wrong. Well I have to read again about pointers. Thanks for correcting me Ipang.

Answer 7

Uttam you cannot combine an integer and a string, if you want it to say "5Sololearn", then cover the 5 in quotes.

Answer 8

this is a pointer.
If you want to write 5Sololearn just write that ;
cout<<"5 Sololearn;
I GUESS YOU MUST REVIS. YOU LESSONS AT C++ and
that's all.

Answer 9

Also Uttam, the reason it prints "earn" is because 5 is the 6th place in the string (0, 1, 2, 3, 4, 5) and it acts like an arry. If you did cout << 4 + "SoloLearn", the output would be Learn instead of earn.