Tripple dollar. Please explain me, step by step, what does interpreeter do here and why it outputs dollardollar?

Question

code:

$dollar = "dollar";
$dollar = $dollar."dollar";
$dollardollar = $dollar;
echo $$dollar;

Answer 1

(I'm not sure if that kind of imaginary parentheses helps, but I'hope that such verbal step by step explanation is clear anyway... you just have to "parse and evaluate" those multiple "quot; yourself like interpreter does.)

Answer 2

This is pretty self explanatory as it creates two strings of dollar joins them and the result is dollardollar

Answer 3

1st line: $dollar is equal to dollar.
2nd: see $dollar as $($dollar), now put a value of $dollar instead of $dollar and you'll get $(dollar), now drop those parentheses;
now, $dollar equals concatenated $dollar (it's value, which is "dollar") and string literal "dollar". (So, now $dollar equals "dollardollar").
3rd: a new variable comes here, it's $dollardollar and it equals "dollardollar" too.
4th: You can imagine some parentheses here again for those variable variables. $($($dollar)). So, evaluate "first" "expression" here (inside parentheses). $dollar equals "dollardollar" and now we have $($(dollardollar)). Drop the pair of parentheses as we have already evaluated "expression" inside... $($dollardollar). Evaluate again. $dollardollar equals "dollardollar" so we have $(dollardollar). Drop the last pair of parentheses and you'll have last and long waited variable here: $dollardollar which value is "dollardollar" and echo $dollardollar outputs "dollardollar".

Answer 4

BroFarOps Please help this guy...!

Answer 5

Hi.
I manage to solve it out few days ago with my friend who works in IT and forgot about this question topic.
However this explanation is exactly what I requested for.
Thank you much for your effort.
Take care.
Greets.