A program in C to print nth term of series 1 1 3 2 9 4 27 8 81 16........

Question

at odd position there is a diff series and at even position there is a different one

Answer 1

shubhangi please let us know your query... note that people will not do entire coding for you..

if you are unable to get series , refer below :

odd position is number at last position multiply by 3... so, you have 1,3,9,27,81 etc
even position is number at last position multiply by 2.

Answer 2

#in Python this is what I would do
print(*[(2**(n//2) if n%2 else 3**(n//2)) for n in range(10)])

Answer 3

shubhangi , refer below :

int main()
{
int n = 10;
int intLast_2=1;
int intLast_3 =1;

printf("%d\n",intLast_2);
printf("%d\n",intLast_3);

for(int i=1;i<(n/2);++i)
{
intLast_2 *= 2;
intLast_3 *= 3;
printf("%d\n",intLast_2);
printf("%d\n",intLast_3);
}

return 0;
}

Answer 4

i know no one will do the entire coding. but i just want the idea to perfom this coding. the 2 different seriea i know them what the are at even places it is 2 to tha power 0 to n
and at odd places it is 3 to the power 0 to n