how the code works ?

Question

n = 2
a = [[0] * n for i in range(n)]

Output is -->
[[0,0] , [0,0]]

Please explain the output how it has come ?

Answer 1

a = [[0]*2 for i in range(2)]

[0]*2 = [0]+[0] = [0,0]

range(2) contains 2 numbers so [0,0] is used twice.

result is a list containing [0,0] twice.