why cout << i==‘1’ causes an error?

Question

https://code.sololearn.com/c6wLOPzA10dY/?ref=app
In this code:
Int i=5;
cout << i==‘1’
Causes an error

However,
cout << (i==‘1’)
Prints 0?

Answer 1

The overloaded insertion << operator has higher precendence over == operator.

Answer 2

i see, now it makes sense, it would be nice if << operator was explained in advanced c++ tutorial

Answer 3

yes